Question

Find two consecutive positive integers, sum of whose square is 365​

Answer 1

Hope This Helps....

Mark as Brainliest...

Answer 2

Answer:

13 and 14

Step-by-step explanation:

let one number be X

another be X+1

so

(X+1)^2 + (X)^2= 365

x^2 + 1 + 2x +x^2 =365

2x^2 + 2x - 364 =0

divide both sides by 2

x^2 +1x - 182 =0

x^2 -14x+13x - 182 =0

x(x - 14 ) + 13 (x- 14)= 0

(X- 13) ( x- 14)

x=13 x= 14

here is your answer hope it will help u