Question

Find two consecutive positive integers,sum of whose square is365

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

let one of the integers be x

The consecutive positive integers

∴ x² + (1 + x²) = 365

∴ x² + x² = 365 - 1

∴ 2x² = 364

∴ x² = 364/2

∴ x² = 182

∴ x = $\sqrt{182}$

∴ x = 13

Step-by-step explanation: