Question

find two consecutive positive integers sum of whose square is 365​

Answer 1

Answer:

The ans is 13 and 14.

Hope it helps...

Answer 2

Answer:13,14

Step-by-step explanation:

Let the consecutive no.s be x and x+1.

So their squares are x²and (x+1)²

According to the question,

x²+(x+1)²=365

Expanding it, we get

x²+x²+2x+1=365

2x²+2x=364

x²+x-182=0

By splitting the middle term,

x(x+14)-13(x+14)

(x-13)(x+14)

we get x=13, -14

Rejecting the negative value,x=13

So the consequtive no.s are 13 and 14, where 13 is x and 14 is x+1