Question

Find two consecutive positive integers ,sum of whose square 365​

Answer 1

hey mate here is your answer

the two numbers be x , x+1

so given

x² + (x+1)² = 365

x² + x² + 1 + 2x = 365

2x² + 2x - 364 = 0

x² + x - 182 = 0

x² + 14x - 13x - 182 = 0

x(x + 14) - 13(x + 14) = 0

(x - 13)(x + 14) = 0

so x = 13 

 so the 

consecutive numbers are 13,14

Answer 2

Answer:

$13 \: and \: 14$

Step-by-step explanation:

It is the correct answer.

Hope this attachment helps you.