Question

Find two consecutive positive integers,sum of whose square is 365.​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

this is your answer dear have a good day

$ANSWER</p><p></p><p>Let the two consecutive positive integers be x and x+1</p><p>Then,</p><p>x2+(x+1)2=365</p><p>⇒x2+x2+2x+1=365</p><p>⇒2x2+2x−364=0</p><p>⇒x2+x−182=0</p><p>Using the quadratic formula, we get</p><p>x=2−1±1+728</p><p>⇒2−1±27</p><p>⇒x=13 and x=−14</p><p>But x is given to be a positive integer. ∴x=−14</p><p>Hence, the two consecutive positive integers are 13 and 14.</p><p></p><p>$