Question

find two consecutive positive integers sum of whose square is 925​

Answer 1

Step-by-step explanation:

Let the integers be x and (x + 1)

x² + (x + 1)² = 925

x² + x² + 2x + 1 = 925

2x² + 2x + 1 = 925

2x² + 2x - 924 = 0

x² + x - 462 = 0

This equation is in the form

Ax² + Bx + C = 0

a = 1, b = 1, c = -462

Now, plug these values into the Quadratic Formula

x = [-b ± sqrt (b² - 4ac)]/2a

Answer 2

Step-by-step explanation:

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