Question

find two consecutive positive integers sum of whose squares is 613​

Answer 1

Step-by-step explanation:

refer attachment.........

Answer 2

Step-by-step explanation:

let the two consecutive integers be

x sq. + ( x+1) sq. = 613

x² + x² + 1 + 2x = 613

2x² + 2x = 613 - 1

2x² + 2x - 612 = 0

2 ( x² + x - 306 ) = 0

x² + x - 306 = 0

x² - 18x + 17x - 306 = 0

x (x - 18) + 17 (x - 18) = 0

(x - 18) (x + 17) = 0

x = 18

x = -17

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