Question

Find two consecutive positive integers sum of whose squares is 365. ​

Answer 1

• Answer:13&14
• Step-by-step explanation:13^2=169
• 14^2=196
• 169+196=365

#hope help you

Answer 2

Step-by-step explanation:

Assumption: Let the consecutive positive integers be x and (x+1).

According to the question,

x² + (x+1)² = 365

Or, x² + (x² + 1 + 2x) = 365

Or, 2x² + 2x + 1 = 365

Or, 2x²+2x+1-365=0

Or, 2x²+2x-364=0

Or, 2(x²+x-182)=0

Or, x²+x-182= 0/2

Or, x²+x-182 =0

Or, x²+14x-13x-182=0

Or, x(x+14)-13(x+14)=0

Or, (x+14)(x-13)=0

Or, x-13=0/(x+14)

Or, x-13=0

Or, x=13

Therefore the consecutive positive integers are 13(x) and 14 (x+1).