Question

find two consecutive positive integers sum of whose squares is 365​

Answer 1

Answer:

NOW SQUARE OF TWO CONSIQUTIVR INTIGER ID

X2 +X2 +2X+1= 365

2X2 +2X=364

X² +X= 182

X2 +14x -13x -182

(x-13) (x+14)

x= 13

no. are 13 and 14

Answer 2

Let. The two. Positive consecutive integers are x and x+1

Given : x^2 +(x+1)^2 = 365

X^2 +x^2 +1 +2x = 365

2x^2 + 2x - 364= 0

X = - 14, 13

-14 will be neglected

As it asked for posttive value

So x = 13

X+1 =14