Question

find two consecutive positive integers sum of whose squares is 365​

Answer 1

Answer:

13 and 14

Step-by-step explanation:

Answer 2

Step-by-step explanation:

let two consecutive positive integers be x,x+1,

then, atq, x^2+(x+1)^2=365

x^2+x^2+2x+1=365

2x^2+2x=365-1=364

2(x^2+x)=364

x^2+x=364/2=182

x^2+x-182=0

x^2+14x-13x-182=0

x(x+14)-13(x+14)=0

(x+14)(x-13)=0

x=-14,x=13

since no. is positive integer, hence, x=13

then 2nd consecutive interger=x+1=14