Question

Find two consecutive positive integers, sum of whose squares is 365.​

Answer 1

let the integers be x & x+1

given:-

x²+(x+1)²= 365

2x²+2x+1=365

x²+x-182 = 0

x²+14x-13x-182= 0

x = -14,13

so the numbers are 13,14

-13 will be rejected as asked numbers must be positive.

hope it helped you

please mark it as the brainliest answer

Answer 2

Answer:

$13 \: and \: 14$

Step-by-step explanation:

It is the correct answer.

Hope this attachment helps you.