Question

find two consecutive positive integers sum of whose squares is 365​

Answer 1

Step-by-step explanation:

I have attached the answer

Answer 2

Let the no. Be x, x+1

Then we have, x²+(x+1)²=365

x²+x²+2x+1=365

2x²+2x-365=0

x²+x-182=0

x²+14x-13x-182=0

x(x+14)-13(x+14)=0

(x+14) (x-13)=0

x=-14, x=13

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