Find two consecutive positive integers ,sum of whose squares is 1405
Answers
Answered by
2
Answer:
Let us assume x,x+1 be the two consecutive positive integers, Therefore
x
2
+(x+1)
2
=613
x
2
+x
2
+2x+1=613
2x
2
+2x+1=613
2x
2
+2x−612=0
2(x
2
+x−306)=0
x
2
+x−306=0
x
2
−18x+17x−306=0
x(x−18)+17(x−18)=0
(x−18)(x+17)=0
Therefore, x=18 or −17
Answer is x=18 and 17.
Step-by-step explanation:
➡️Plz follow me and thank my answers dude ❤
Similar questions