Find two consecutive positive integers, sum of whose squares is 365.m.
Answers
Answered by
1
Answer:
13 and 14
Hence, the two consecutive positive integers are 13 and 14
Step-by-step explanation:
hope it helps you...
Answered by
1
100+121+144 = 365
=> 10²+11²+12² = 365
I hope ur question may be of 3 consecutive numbers.
if we try 2 we won't get
I will say proof for 3
Step-by-step explanation:
proof
let the 3 consecutive numbers be x-1, x, x+1
given, (x-1)²+x²+(x+1)² = 365
=> x²+1-2x+x²+x²+1+2x = 365
=> 3x²+2 = 365
=> 3x² = 363
=> x² = 121
=> x = 11 ( as the numbers are positive integers)
=> other numbers are 11-1, 11+1
=> 10, 12
the numbers are 10,11,12
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