Question

Find two consecutive positive integers, sum of whose squares is 365.m. ​

Answer 1

Answer:

13 and 14

Hence, the two consecutive positive integers are 13 and 14

Step-by-step explanation:

hope it helps you...

Answer 2

100+121+144 = 365

=> 10²+11²+12² = 365

I hope ur question may be of 3 consecutive numbers.

if we try 2 we won't get

I will say proof for 3

Step-by-step explanation:

proof

let the 3 consecutive numbers be x-1, x, x+1

given, (x-1)²+x²+(x+1)² = 365

=> x²+1-2x+x²+x²+1+2x = 365

=> 3x²+2 = 365

=> 3x² = 363

=> x² = 121

=> x = 11 ( as the numbers are positive integers)

=> other numbers are 11-1, 11+1

=> 10, 12

the numbers are 10,11,12