Math, asked by Anonymous, 1 day ago

Find two consecutive positive integers, sum of whose squares is 365 ?​

Answers

Answered by llitzurRiyull
18

Step-by-step explanation:

Let the two consecutive positive integers be x and x+1

Let the two consecutive positive integers be x and x+1Then,

Let the two consecutive positive integers be x and x+1Then,x

Let the two consecutive positive integers be x and x+1Then,x 2

Let the two consecutive positive integers be x and x+1Then,x 2 +(x+1)

Let the two consecutive positive integers be x and x+1Then,x 2 +(x+1) 2

Let the two consecutive positive integers be x and x+1Then,x 2 +(x+1) 2 =365

Let the two consecutive positive integers be x and x+1Then,x 2 +(x+1) 2 =365⇒x

Let the two consecutive positive integers be x and x+1Then,x 2 +(x+1) 2 =365⇒x 2

Let the two consecutive positive integers be x and x+1Then,x 2 +(x+1) 2 =365⇒x 2 +x

Let the two consecutive positive integers be x and x+1Then,x 2 +(x+1) 2 =365⇒x 2 +x 2

Let the two consecutive positive integers be x and x+1Then,x 2 +(x+1) 2 =365⇒x 2 +x 2 +2x+1=365

Let the two consecutive positive integers be x and x+1Then,x 2 +(x+1) 2 =365⇒x 2 +x 2 +2x+1=365⇒2x

Let the two consecutive positive integers be x and x+1Then,x 2 +(x+1) 2 =365⇒x 2 +x 2 +2x+1=365⇒2x 2

Let the two consecutive positive integers be x and x+1Then,x 2 +(x+1) 2 =365⇒x 2 +x 2 +2x+1=365⇒2x 2 +2x−364=0

Let the two consecutive positive integers be x and x+1Then,x 2 +(x+1) 2 =365⇒x 2 +x 2 +2x+1=365⇒2x 2 +2x−364=0⇒x

Let the two consecutive positive integers be x and x+1Then,x 2 +(x+1) 2 =365⇒x 2 +x 2 +2x+1=365⇒2x 2 +2x−364=0⇒x 2

Let the two consecutive positive integers be x and x+1Then,x 2 +(x+1) 2 =365⇒x 2 +x 2 +2x+1=365⇒2x 2 +2x−364=0⇒x 2 +x−182=0

Let the two consecutive positive integers be x and x+1Then,x 2 +(x+1) 2 =365⇒x 2 +x 2 +2x+1=365⇒2x 2 +2x−364=0⇒x 2 +x−182=0Using the quadratic formula, we get

Let the two consecutive positive integers be x and x+1Then,x 2 +(x+1) 2 =365⇒x 2 +x 2 +2x+1=365⇒2x 2 +2x−364=0⇒x 2 +x−182=0Using the quadratic formula, we getx=

2−1±

−1± 1+728

−1± 1+728⇒x=13 and x=14

the two consecutive positive integers are 13 and 14.

Answered by Protish
1

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