find two consecutive positive integers , sum of whose squares is 613.
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Answered by
1
Answer:
Let us assume x,x+1 be the two consecutive positive integers, Therefore
x 2+(x+1) 2
=613
x 2 +x 2+2x+1=613
2x 2+2x+1=613
2x 2 +2x−612=0
2(x 2 +x−306)=0
x 2+x−306=0
x 2−18x+17x−306=0
x(x−18)+17(x−18)=0
(x−18)(x+17)=0
Therefore, x=18 or −17
Answer is x=18 and 17
Answered by
5
Answer:
Given that sum of consecutive positive integers is 613. ... So , The two consecutive positive integers are 17 & 18
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