Find two consecutive positive integers sum of whosesquares is365
Answers
Answered by
1
Answer:
Let the first number be x
Therefore, second number = x+1
According to question:
x² + (x+1)² = 365
x² + x² +1 + 2x = 365
2x² +2x + 1 - 365 = 0
2x² + 2x -364 = 0
x² + x - 182 = 0
then solve it using quadratic formula or completing the square.
It is a helping platform not tell me the answer.
You should always write what you have tried with the question.
otherwise your teacher is the best person to whom you can ask
Answered by
0
Answer:
(13 and 14) is right answer.
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