Question

find two consecutive positive integers sum whose square is 365

Answer 1

let the no. be  x and x+1

  then we have x²+(x+1)²=365

                     2x²+2x-364=0

                     x²+x-182=0

                     x²+14x-13x-182=0

                     (x+14)(x-13)=0

                 That gives x=13 Avoiding negative value

                 one number is 13 and other one is 14

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Answer 2

Answer:

let the numbers be x and x+1

x^2+(x+1)^2=365

2x^2+2x-364=0

x^2+x-182=0

x=13

hence numbers=13,14

Step-by-step explanation: