Question

Find two consecutive positive integers,the sum of whose squares is 365
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Answer 1

let 1st positive integer be x

second positive integer be x+1

according to question

(x)2+(x+1)2=365

x^2+x^2+2 x+(1)2=365

2 x 2+2 x−364=0

x^2+x−182=0

x^2+14 x−13 x−182=0

x(x+14)−13(x+14)=0

(x+14)(x−13)=0

x=−14 or 1 3

cant take negative value so

x=13  

x+1=14

hope it helps mark me as brainliest please

Answer 2

Answer:

$13 \: and \: 14$

Step-by-step explanation:

It is the correct answer.

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