Math, asked by Anonymous, 6 months ago

find two consecutive positive integers whose product is 12.

Answers

Answered by Anonymous
3

Answer:

3 and 4

Step-by-step explanation:

te product of 3 and 4 is 12

Answered by Smrutipratikshya
4

Answer:

Notice that consecutive odd integers will differ by 2, so we could call the even number between them n, making the two integers n−1 and n+1.

So:

143=(n−1)(n+1)=n2−1

Add 1 to both ends and transpose to get:

n2=144=122

So n=±12

Since we are told that the integers are positive, use n=12 to find the pair of integers: 11,13.

Alternatively, just find factors of 143, trying prime numbers in turn: 2 (no), 3 (no), 5 (no), 7 (no), 11 (yes). Then 14311=13 - we have found our pair of numbers.

Step-by-step explanation:

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