find two consecutive positive integers whose product is 12.
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Answered by
3
Answer:
3 and 4
Step-by-step explanation:
te product of 3 and 4 is 12
Answered by
4
Answer:
Notice that consecutive odd integers will differ by 2, so we could call the even number between them n, making the two integers n−1 and n+1.
So:
143=(n−1)(n+1)=n2−1
Add 1 to both ends and transpose to get:
n2=144=122
So n=±12
Since we are told that the integers are positive, use n=12 to find the pair of integers: 11,13.
Alternatively, just find factors of 143, trying prime numbers in turn: 2 (no), 3 (no), 5 (no), 7 (no), 11 (yes). Then 14311=13 - we have found our pair of numbers.
Step-by-step explanation:
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