find two consecutive positive integers whose sum is 63.
Answers
Answered by
467
Hey friend!
_____________
Here is your answer
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Let,
1st number = x
2nd number = x + 1 ( consecutive numbers)
Thus,
x + x + 1 = 63
2x + 1 = 63
2x = 63 - 1
2x = 62
x = 62 ÷ 2
x = 31
There fore the numbers are:
x = 31
x + 1 = 31 + 1 = 32
= 31 and 32
_________________________________________________________
HOPE THIS HELPS YOU :)
_____________
Here is your answer
___________________
Let,
1st number = x
2nd number = x + 1 ( consecutive numbers)
Thus,
x + x + 1 = 63
2x + 1 = 63
2x = 63 - 1
2x = 62
x = 62 ÷ 2
x = 31
There fore the numbers are:
x = 31
x + 1 = 31 + 1 = 32
= 31 and 32
_________________________________________________________
HOPE THIS HELPS YOU :)
Answered by
45
Step-by-step explanation
let one no is x
then another no will be x+1
Now according to question,
x+x+1=63
=> 2x =63-1
=> 2x =62
=> x = 62/2
=>x =31
then another no= x+1
=31+1
=32
so both consecutive no.s are 31 and 32.
Hope it helps u mate.....thank u..... ✌✌✌
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