find two consecutive positive integers whose sum is 63
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Answer:
The numbers are 31 & 32.
Step-by-step explanation:
Let the 1st no. be = x
2nd no. = x + 1
So now, A/Q
= x + x + 1 = 63
= 2x + 1 = 63
= 2x = 63 - 1
= x = 62 ÷ 2
= x = 31
So, the no.s are =
= x = 31 , ( 1st no.)
= x + 1 (2nd no.)
= 31 + 1 = 32
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