Question

find two consecutive positive integers whose sum is 63

Answer 1

Let,

1st number = x

2nd number = x + 1 ( consecutive numbers)

Thus,

x + x + 1 = 63
2x + 1 = 63
2x = 63 - 1
2x = 62
x = 62 ÷ 2
x = 31

Therefor the numbers are:

x = 31
x + 1 = 31 + 1 = 32
= 31 and 32

Answer 2

x+(x+1) = 63
2x + 1 = 63
x= 62/2
x= 31
the numbers are 31 and 32