find two consecutive positive integers whose sum is 63
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Answered by
2
Answer:
Let the first integer = x
the second consecutive integer = x + 1
According to question
x + x + 1 = 63
2x + 1 = 63
2x = 63 - 1
2x = 62
x = 62 / 2
x = 31
So the first integer = x = 31
And the second integer = x + 1 = 31 + 1 = 32
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Answered by
1
Answer:
Let,
1 st number = x
2 nd number =x+1 _______( consecutive numbers)
Thus,
x+x+1=63
2x+1=63
2x=63−1
2x=62
x=62/2
x=31
x+1=31+1=32
∴
The required numbers are 31 and 32
I hope it will help you ✌️
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