Find two consecutive positive integers whose sum of square if 290
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Hey !!!!!!
let the consecutive positive integers be x and x + 1.
Therefore ATQ,
x² + ( x + 1 )² = 290
x² + x² + 1 + 2x = 290
2x² + 2x = 289
2x² + 2x - 289 = 0
There seems to be some problem with the question because it's not getting factorised.
let the consecutive positive integers be x and x + 1.
Therefore ATQ,
x² + ( x + 1 )² = 290
x² + x² + 1 + 2x = 290
2x² + 2x = 289
2x² + 2x - 289 = 0
There seems to be some problem with the question because it's not getting factorised.
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12
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