Find two consecutive positive multiples of 3 whose product Ispecifications 270
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Answer:
15 ,18
Step-by-step explanation:
Let the two consecutive multiples of 3 be 3x and 3x+3
Given that their product=270
⇒3x(3x+3)=270
⇒9x(x+1)=270
⇒x(x+1)=30
⇒x2+x−30=0
⇒x2+6x−5x−30=0
⇒x(x+6)−5(x+6)=0
⇒(x+6)(x−5)=0
⇒x=−6,5
Considering the positive value of x
⇒x=5,3x=3×5=15 and 3x+3=15+3=18
∴ The two consecutive multiples of 3 are 15 and 18
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