find two consecutive positive multiples of 3 whose product is 270
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Answered by
5
Hello here is your answer by Sujeet yaduvanshi ☝☝☝☝☝☝☝☝☝☝
Let to be first consecutive Number x
Then,
Second consecutive Number=X+3
Again,
x(x+3)=270
x²+3x-270=0
x²+18x-15x-270=0
x(x+18) -15(x+18)0
(x+18)(x-15)
then,
Number will be 18,15
that's all
Let to be first consecutive Number x
Then,
Second consecutive Number=X+3
Again,
x(x+3)=270
x²+3x-270=0
x²+18x-15x-270=0
x(x+18) -15(x+18)0
(x+18)(x-15)
then,
Number will be 18,15
that's all
priteshrathwa:
I want it in one variable sorry for not selecting your answer as brain list
Answered by
3
Do x (x+3)=270 and then solve the eq
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