Question

find two consecutive positive natural number whose square sum is 365​

Answer 1

Answer:

Let the two consecutive positive integers be x and x + 1 Then, x^2 + (x + 1)^2 = 365 x^2 + x^2 + 2x + 1 = 365 2x^2 + 2x - 364 = 0 x^2 + x - 182 = 0 Using...Read more