Question

Find two consecutive positive numbers whose square have the sum 85

Answer 1

Answer:

let the two consecutive numbers be be x and ( x+1)

x^2+(x+1)^2=85

x^2+x^2+1+2x=85

(2x^2+2x=85-1)÷2

x^2+x=42

x^2+x-42=0

x(x+7)-6(x+7)=0

(x+7)(x-6)=0

x =-7 or x=6

then x+1=6 +1=7