Question

Find two consecutive positive odd integer whose product is 483

Answer 1

Answer:

1st number x

2nd number= x+2

so: x(x+2) 483

x2 2x -483= 0

making the factors of equation we get

x2 23x 21x -483= O

(x-21) x 23)= 0

x= 21

X -23

so 1st no= 21

2nd no 23

Answer 2

• Let two consecutive odd numbers be a and a + 2.

The product of these two numbers is 483.

=> a(a + 2) = 483

=> a² + 2a = 483

=> a² + 2a - 483 = 0

=> a² + 23a - 21a - 483 = 0

=> a(a + 23) - 21(a + 23) = 0

=> (a + 23) (a - 21) = 0

• a + 23 = 0

=> a = - 23 (neglected)

• a - 21 = 0

=> a = 21

______________________________

First number = a = 21

Other number = a + 2 = 21 + 2 = 23

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