Question

find two consecutive positive odd integers whose sum is 132..using any variable
Sol:- ???​

Answer 1

Answer:

• n(n + 1) = 132 (n + 12)(n - 11) = 0 n2 + n = 132 n = -12 or n = 11. n2 + n – 132 = 0 Since the answer is a positive integer, throw out -12 answer. The two consecutive positive integers whose product is 132 are 11 and 12..

• Which means that the first number is 43, the second number is 43 + 1 and the third number is 43 + 2. Therefore, three consecutive integers that add up to 132 are 43, 44, and 45. We know our answer is correct because 43 + 44 + 45 equals 132 as displayed above.

Step-by-step explanation:

hope it will help you something

Answer 2

Answer:

65, 67

65+67 = 132

Step-by-step explanation:

x+x+2 = 132

2x+2 = 132

2x = 132 - 2

2x = 130

x = 65

x+2 = 67