Question

find two consecutive positive odd integers whose sum is 76

Answer 1

Let the required positive odd integers are 2x + 1 and 2x + 3 .



Given in the question that the sum of both the odd Integers is 76.




Therefore, ( 2x + 1 ) + ( 2x + 3 ) = 76


= > 2x + 1 + 2x + 3 = 76


= > 2x + 2x +4 = 76


= > 4x + 4 = 76


= > 4x = 76 - 4


= > 4x = 72


= > 2 × 2x = 72


= > 2x = 72 / 2


= > 2x = 36





Therefore, required positive odd integers are 2x + 1 = 36 + 1 = 37 and 2x + 3 = 36 + 3 = 39



Integers are 37 and 39.

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