find two consecutive positive odd integers whosebsum is 76.
Answers
Answered by
1
Answer:
37 and 39.
Step-by-step explanation:
Answered by
0
Step-by-step explanation:
Let the two consecutive odd integers are 2x+1 and 2x+3
According to the question,
⇒ 2x+1+2x+3=76
⇒ 4x+4=76
⇒ 4x=72
x=
4
__
74
=18
So, one integer=2x+1=37
another one=2x+3=39
∴ The required two consecutive positive odd integers are 37 and 39.
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