Math, asked by kanwalhayaabaloch786, 10 months ago

Find two consecutive positive odd numbers such that the square of their sum exceeds the sum of their squares by 126

Answers

Answered by stameem42

2

Answer:

x+Y=126

Step-by-step explanation:

X=126-Y
X=Y×12
12Y=126-Y
2Y=126-12
2Y=114
Y=114/2
Y=57

Answered by mcgrathgabriel3

0

Answer:

9 and 7

Step-by-step explanation:

JOE MAMA

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