Math, asked by kanwalhayaabaloch786, 1 year ago

Find two consecutive positive odd numbers such that the square of their sum exceeds the sum of their squares by 126

Answers

Answered by stameem42

2

Answer:

x+Y=126

Step-by-step explanation:

X=126-Y
X=Y×12
12Y=126-Y
2Y=126-12
2Y=114
Y=114/2
Y=57

Answered by mcgrathgabriel3

0

Answer:

9 and 7

Step-by-step explanation:

JOE MAMA

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