find two consecutive positive odd numbers such that the sum of their squares is equal to 130
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Answer:
Let first number be x
So, second number = x+2.
so,
x² + (x+2)²=130
=>x² + x² +4 + 4x -130=0
=>2(x² +2x - 63) = 0
=> x² + 9x-7x -63=0
=>x(x+9)-7(x+9)=0
=>(x+9)(x-7)=0
=>x=-9 or x=7
if x=-9, x+2=-7
if x=7, x+2=9
so, no.s are 7 n 9 or -7 n -9
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