Question

find two consecutive positive odd numbers,the sum of whose squares is 802

Answer 1

19 and 21. Sum of 19*19-361and sum of 21*21-441 is equal to 361plus441 - 802

Answer 2

(2k+1)^ +(2k+3)^=802
8k^+ 10 + 8k + 12k =802
8k^+20k=792
4k^+10k =396

I guess you can find roots by formula ofroots for quadratic equation