Question

find two consecutive terms of the sequence sn =n2(square)
(n+ 1)

Answer 1

Put 1 in term n

=(1)2square(1+1)

=4(2)=8

8 is the sum of 1 term

So a1 is 8

For getting sum of first two terms

Put 2 in n

(1)2 square (1+2)

4(3)

=12

So sum of first two terms is 12

a1+a2=12

8+a2=12

a2=12-8

=4

Ap=8,4