find two consecutive whole number the difference of whose reciprocal is 1/12
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Answer:
The consecutive whole numbers can be called
x, x+1
The reciprocal of x = 1/x
The reciprocal of x+1 = 1/(x+1)
1/x - 1/(x+1) = 1/12
Get a common denominator on the left side
of x(x+1)
[(x+1) - x]/[x(X+1)] = 1/12
1/(x2+x) = 1/12
Cross multiply
x2+x=12
x2+x-12 = 0
(x+4)(x-3) = 0
X = -4 or x=3
Your consecutive whole numbers are
-4, -3 or 3, 4
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