Question

find two consecutive whole numbers whose product is 72​

Answer 1

x= 1st integer

x+1= 2nd integer

x(x+1) = 72

x^ + 1x + 72

x^ + 1x -72 = 0

(x+9)(x-8)

if u solve u'll get x=-9 and x=8

x can't be negative.

so x=8

x=8=1st integer

x+1=8+1=9=2nd integer.

Answer 2

Answer:

Let the two consecutive numbers be x and x+1.

Their product is given as 72. Therefore,

x(x+1)=72

⟹x2+x=72

⟹x2+x−72=0

Solving the above quadratic equation,

⟹(x+9)(x−8)=0

⟹x=−9,8

If x = -9, then x+1 = -8. Thus, the required numbers would be -9, -8.

If x = 8, then x+1 = 9. Thus, the required numbers would be 8, 9.

Thus, the required consecutive numbers are either -9, -8 or 8, 9.

Step-by-step explanation:

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