find two consicutive natural number whose product is 20
Answers
Answered by
3
Answer:
Ans :4,-5
Hint :
Let the numbers be x and x + 1. Then,
x(x + 1) = 20
⇒x
2
+ x - 20 = 0
⇒(x+5)(x−4)=0
Answered by
1
Answer:
4 and 5
Step-by-step explanation:
Let n be the natural number then next consecutive number will be ( n + 1)
it's given that
n(n+1) = 20
n^2 + n = 20
n^2 + n - 20 = 0
n^2 + 5n - 4n -20 =0
n(n+5) -4( n + 5) = 0
( n+ 5) ( n - 4) = 0
so either n = -5 or n = 4
but we let that n is a nautral number
so only value of n acceptable here is 4
so n = 4 first number
second number = ( n + 1) = 5
so the numbers are 4 and 5
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