find two cosecutive natural number whose squares have the sum 265
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let the numbers be x and x+1
x^2+(x+1)^2=265
x^2+x^2+1+2x=265
2x^2+2x+1=265
2x^2+2x-264=0 ÷2
x^2+x-132=0
x^2+12x-11x-132=0
x(x+12)-11(x+12)=0
(x+12)(x-11)=0
x=-12 or 11
the numbers are -12 and -11
OR
the numbers are 12 and 11
Hope it helps you
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x^2+(x+1)^2=265
x^2+x^2+1+2x=265
2x^2+2x+1=265
2x^2+2x-264=0 ÷2
x^2+x-132=0
x^2+12x-11x-132=0
x(x+12)-11(x+12)=0
(x+12)(x-11)=0
x=-12 or 11
the numbers are -12 and -11
OR
the numbers are 12 and 11
Hope it helps you
Mark it brainliest
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