Find two different solution for the equation 3x-8y=27
Answers
Answered by
23
3x-8y =27---(1)
1) if x=0
-8y=27
y=(-27/8)
2)if y=0
3x=27
x=27/3
x=9
therefore two solutions are
(0, -27/8) and (9,0)
1) if x=0
-8y=27
y=(-27/8)
2)if y=0
3x=27
x=27/3
x=9
therefore two solutions are
(0, -27/8) and (9,0)
mysticd:
thank you selecting as brainliast
Answered by
7
your answer is in this pic
Attachments:
Similar questions