find two different solution of the equation 5x-3y=19
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1. 5(0)-3y =16
-3y = 16
y =16/3
5x -3{0} =16
x = 16/5
2. 5(1) -3y =16
5 -3y =16
-3y = 16 -5
-3y = 11
y = -11/3
5x - 3(1) =16
5x -3 =16
5x = 16 +3
x = 19/5
3. 5{2) -3y =16
10 -3y =16
-3y =16-10
-3y = 6
y = 6/-3 =-2
5x -3{2} =16
5x -6 =16
5x = 16 +6
5x = 22
x = 22/5
4. 5{4} -3y =16
20 -3y =16
-3y = 16-20
y = -4/-3
y = 4/3
5x -3{3} =16
5x -9 =16
5x = 16 +9
5x = 25
x = 25/5 =5
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