find two different solutions of linear equation 3x+2y=12
Answers
Answered by
0
Step-by-step explanation:
For x=0
y=
1−0/2
=0.5
For x=1
y= 1-3/2
-2/2
=-1
Answered by
0
Answer:
y=6 and x=0
y=3 and x=2
Step-by-step explanation:
let y will be 6
by putting value
= 3x+2(6)=12
3x+12=12
3x=12-12
x=0/3
x=0
Now take y=3
by putting value
=3x+2(3)=12
=3x+6=12
=3x=12-6
=x=6/3
=x=2
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