Question

• find two-digit number which has the square of the sum of its digits equal to the number obtained by reversing its digits. ​

Answer 1

Answer:

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Answer:

Let x = the 10's digit

Let y = the units

then

10x+y = the number

(x + y)^2 = 10y + x

Rather than solving this equation, use some assumptions and logic

10y+x has to be perfect square which has two digits, not many of those.

Start with 81, then y=8, x=1

then 18 is the original number and sure enough (1+8)^2 = 81

need brainlist please help your ans hope it is correct

Answer 2

Answer:

81 is the answer

Step-by-step explanation:

if answer is correct please mark me as the brainlist answer