Question

find two factors of the polynomial
p(x) = x^3-4x^2+3x+8?​

Answer 1

Answer:

Let the function be represented by f(x).

As x−2, exactly divides f(x), 2 is the zero of f(x)

Hence, f(2)=0.

f(x)=x

3

+4x

2

−px+8

⇒f(2)=2

3

+4×2

2

−p×2+8=0

⇒2p=32

⇒p=16