Question

Find two integers whose difference is 4 and whose squares differ by 72.
​

Answer 1

Answer:

Let those 2 integers be x and y.

And X be greater than y.

=> x-y = 4 -------(1)

=> x²- y² = 72

=> (x+y)(x-y) = 72

=> 4(x+y) = 72

=> x + y = 72/4

=> x+y= 18 ----------(2)

On adding equation 1 and 2,

we get,

2x = 22

=> x = 22/2

=> x = 11

=> y = 18-11

=> y = 7

Thus, the two integers are 11 and 7.