Find two integers whose product is 36 and whose sum is 13
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The two integers are 18 and -2.
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Solution :-
As condition provided :-
• Sum of Integers = 13
• Product of Integers = 36
Let the Integers be x and 13-x
Now as product = 36
=> x (13 - x) = 36
=> 13x - x² = 36
=> 0 = x² - 13x + 36
=> x² - 13x + 36 = 0
Now we will solve the Quadratic equation.
=> x² - 13x + 36 = 0
=> x² - 4x - 9x + 36 = 0
=> x(x - 4) -9(x - 4) = 0
=> (x - 4)(x - 9)
So Value of x = 4 , 9
Now when
x = 4
13- x = 9
When
x = 9
13 - x = 4
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