Question

Find two integers whose sum is 2 and difference is 8​

Answer 1

Step-by-step explanation:

a = first integer

b = second integer

a + b = 2

a = 2 - b

a - b = 8

2 - b - b = 8

2 - 2 b = 8

- 2 b = 8 - 2

- 2 b = 6

b = 6 / - 2

b = - 3

a = 2 - b

a = 2 - ( - 3 )

a = 2 + 3

a = 5

Answer 2

Answer:

$x + y = 2 \\ x - y = 8 \\ - - - - - - - \\ 2x = 10 \\ x = \frac{10}{2} \\ x = 5 \\ x + y = 2 \\ 5 + y = 2 \\ y = 2 - 5 \\ y = - 3$

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