Question

find two irrational no of the form p/q between the numbers 0.2121121112 and 0.2020020002​

Answer 1

Consider x and y as the two rational numbers lying between 0.2121121112.... and 0.2020020002....

We know that,

0.2020020002.<0.2121121112

We get,

0.2020020002<x<y<0.2121121112

x=

250

51

=0.204

y=

500

103

=0.206.

Answer 2

Answer:

The numbers are $\frac{51}{250}, \frac{103}{500}$.

Step-by-step explanation:

Given two numbers are $0.2121121112$ and $0.2020020002$.

We need to find two irrational numbers of the form p/q between the numbers.

The irrational numbers are all the real numbers which are not rational numbers. That is, irrational numbers cannot be expressed as the ratio of two integers.

Consider $x$ and $y$ as the two rational numbers lying between $0.2121121112$ and $0.2020020002$.

We know that,

$0.2020020002<0.2121121112$.

We get

$0.2020020002<x<y<0.2121121112$

So the numbers are

$x=\frac{51}{250}=0.204$

$y=\frac{103}{500}=0.206$.